The question is
Today the United States has the equivalent of 400 standard-sized 1000-MW power plants. If electrical energy consumption continues to rise at the present rate of 2% per year, how many additional power plants will be needed in 35 years to meet those needs?
I never ask for help, especially this way, but I am having a brainfart right now. Thanks guys.
Okay all, I am AWFUL with equations, especially in the fields of science. This is my last college class for science, so can somebody help with this Q?
The question is
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The total consumption is 400 x 1000 giving you 400000 MW
It rises at a rate of 2% annually or 1.02 for 35 years.
So after 35 years consumption will be 400000 x 1.02^35 which is about 800000 MW
Given each station is 1000 MW, thats 800 stations or 400 more than present1
This is just a compound interest question in disguise. I'm not going to just give you the answer although it will be at the end, but please try to understand as well.
A = P (1+r/n)^nt
A is the final amount
P is initial investment
r is annual rate of return (in decimal)
n is the number of times compounded per year (irrelevant for this question)
t is the number of years compounded for
So we must first find the amount of power they will need in 35 years:
Which comes to 799956-MW will be power needs in 35 years
now the powerplants we have already will grant us 400,000MW worth of that power
Knowing that each powerplant can only give 1000MW and you cannot round down for this purpose you effective need 400,000 more MW worth of power or 400 additional powerplants1
not enough information, according to your book what is the current load on the system?1
It should be 400*1.02^351
Too engineery for my taste. Can't help. Here for emotional support.1
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