Hi! This is using algebra to model the situation.
M is Michelle's money
R is Rachel's money
W is Wei Yi's money
Things we know:
M = 6R
A) W + R = 1321
B) W + M = 4386
As M = 6R, we can multiply A) by 6 to get
6R + 6W = 7926
and sub in M for 6R
M + 6W = 7926
Now take away M + W = 4586 to get
5W = 3340
divide by 5
W = 668
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Okay GiB MHO PLS.
https://i.imgur.com/WeI3AUF.jpg
668
hopefully I didn t do any calculations mistakes
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Lets assign variables to name for our own ease
Michelle = A
WeiYi = B
Rachel = C
according to given details we get
A + B = 4586 eq.1
B + C = 1321 eq.2
A= 6C eq.3
B= ?
from eq 2
B = 1321 - C eq.4
from eq 1
B = 4586 - A but also A = 6C So,
B = 4586 - 6C now compare it with eq.4 to get value of C
1321 - C = 4586 - 6C rearrange
6C - C = 4586 -1321
5C = 3265
C = 3265/5 = 653 PUT THIS VALUE OF C EQ.2
B + (653) = 1321
B = 1321 - 653 = 668
SO B=668
Hence WeiYi saved $ 668y + x = 4586
y + z = 1321
x = 6z
y = 4586 - 6z
4586 - 6z + z = 1321
5z = 3265
z = 653
y = 668M+W=4586.
W+R=1321
M=6R
Solve for W.
Substituting for M,
6R+W=4586
Solving for W in second equation.
W=1321-R
Substituting
6R+(1321-R)=4586
Solve for R
5R+1321=4586
5R=3265
R=653.
Solving for W in second equation
W+653=1321
W=668i came up with a good 623... approximately
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