Does anyone know how to do this as my teacher has literally gone MIA and my classmates don’t know?
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abc3643 | 956 opinions shared on Education & Career topic.
Master
13 d
REMEMBER: AREA = BASE * HEIGHT / 2
(A) (i) Finding AREA BASE = 8 cm HEIGHT = 6 cm AREA = 8 cm * 6 cm / 2 = 28 cm^2 /2 = 24 cm^2 (ii) Finding h If you look at the triangle closely, 10 can also be the BASE with h as the corresponding HEIGHT. But we already know the area: 24 cm^2 So: AREA = BASE * HEIGHT / 2 24 cm^2 = 10 cm * h / 2 2 * 24 cm^2 = 10 cm * h 48 cm^2 = 10 cm * h 48 cm^2 / 10 cm = h 4.8 cm = h
Before continuing, notice in (A) that we have the triangle described by 2 different pairs of BASE and HEIGHT values. I am going to write the pairs like this: {BASE, HEIGHT} So, the first pair to get the area was {8, 6} and we got the h value from the second pair, {10, h}
That's how to solve these problems... Use one pair where you know both values to get the area solving the (i) part, and then, because you now know the area, use the second pair which will have the h to get the h HEIGHT value in the (ii) part.
So, with that {BASE, HEIGHT} notation, I am going to quickly spell out the answers for the other problems...
(B) The two pairs are {12, 14} and {16, h} and the units are cm. (i) AREA = BASE * HEIGHT / 2 = 12 * 14 /2 = 12 * 7 = 84 cm^2 (ii) AREA = 84 cm^2 = BASE * HEIGHT / 2 = 16 cm * h / 2 So, 2 * 84 cm^2 = 16 cm * h. 176 cm^2 = 16 cm * h 176 cm^2 / 16 cm = h 11 cm = h
(C) The two pairs are {24, 18} and {20, h} and the units are cm. (i) AREA = BASE * HEIGHT / 2 = 24 * 18 / 2 = 24 * 9 = 216 cm^2 (ii) AREA = 216 cm^2 = BASE * HEIGHT / 2 = 20 cm * h / 2 So, 2 * 216 cm^2 = 20 cm * h. 432 cm^2 = 20 cm * h 432 cm^2 / 20 cm = h 21.6 cm = h
For the second one you rotate the triangle and take 12 as the base. By taking 12 as the base, 14 becomes the height. So the area is 0.5×12×14= 84. Now we take 16cm as the base and find h. 0.5×16×h=84 8h=84 h=10.5 cm.
For the last one take 24 cm as the base and 18cm as the height. 0.5×24×18= an area of 216cm Now we take 20cm as the base to find h. 0.5×20×h=216 10h=216 h=21.6cm
That was easy.
Asker
13 d
Thank you so much that was very helpful!! And a way easier method! For the second question is there a reason to rotate the triangle and take 12 as the base or is it just the method and there’s no reason for it?
First to find the area, triangles are basically just halves of squares or diamonds. to find the area, take the length of a line from a vertex (point) of the triangle to a side of the triangle, and the side of the triangle which the vertex intersects, multiply them, then divide by half.
For part (a), you can see that the triangle is a right triangle, therefore you can just treat it like a square cut in half. Multiply the two sides of the triangle on either side of the right angle together and divide by half. for part (b) you're going to take the length of the dashed line running from the vertex and multiply it by the side of the triangle which it intersects, and again divide by half. you will do the same for part (c)
To find h, you are going to apply the principle that area = (line from the vertex) * (side it intersects) all divided by 2 you know the area, and you know the side of the triangle h intersects, so it becomes an algebra problem. Substitute the values in and solve for your one unknown.
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Asker
13 d
Thank you very much!
genericname85 | 231 opinions shared on Education & Career topic.
Master
13 d
the question is sort of asked in a stupid way, cause you need the answer to question (ii) to answer question (i) xD all your answers are here: https://www.omnicalculator.com/math/triangle-height you can just use the calculator or you can look up the formulars and do it manually. Area is simply 0,5x (bxh), b being the longest side.
the trick often is to figure out one of the compound triangles first and then you can just substract the values that are given to know the infividdual lenths you're missing.
Well to find the area of any triangle its 1/2 base x height. All triangles have a total # of angles of 180 That should give you all the info you need to derive from that.
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BeMuse | 296 opinions shared on Education & Career topic.
Guru
13 d
The area of right triangles is 1/2 the base times the height.
ah ok sorry, maybe contact the head of dept/counsellor, sounds like your classmates aren't being very supportive, maybe there are voluntary tutors in your area that could help, I feel like you are being put down by classmates when they say they can't do it tbh, ex teacher here by the way,,,
There was but with covid we do online school and there’s no more maths club unfortunately, I do my homework later in the day as it’s the best time suitable for me to do it so no maths teachers are usually online to help them
Angelina25 | 189 opinions shared on Education & Career topic.
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