Help with geometry question...What is the area of this shape?

Help please? i have no clue how to do this? Just those 2 I NEED TO FIND THE AREA
Help please? I HAVE NO CLUE HOW TO DO THIS?


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Most Helpful Guy

  • 5. the triangle is equilateral triangle so it's area is 2*(3^.5)/2=(3^.5) m^2
    The entire box is 2*2=4 m^2 so the box minus the triangle is (4-(3^.5)) m^2.

    6. the triangle is 2*5*5*(3^.5)/2=25(3^.5) in^2
    The semicircle area is (5^2)*pi/2=25/2*pi in^2
    Multiply the semicircles by three and add to the triangle to get: [25(3^.5) + 75/2 *pi]] in^2

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What Guys Said 2

  • Come on, they are really simple. In the first shape, you have 2 triangles. There's a little gap on the left, I'm not sure if that was intended, but in case it was, you need to extend the diagonal lines of both, which creates a third triangle. Add up the area of both triangles and take off the area of the smaller one (because otherwise you'd have that one twice).

    The other shape you 3 half circles and 1 triangle. You know the diameter of each circle is 10 in.

    It doesn't get much simpler than this.

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    • Wrong, just solve for the square, and subtract the triangle.

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    • The length of the gap would be unknowable your way..

    • I suppose so but I also just like the exercise..

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    • But seriously, solve for the square, then the triangle. Subtract triangle from square and BOOM.

      Then for the other, solve triangle, then full circle and and a half circle.

What Girls Said 1

  • i dont know if this is right or not but here goes...
    Q5) 2*2=4
    0.5*2*2=2
    4-2=2cm^2
    Q6) 0.5*10*10=50
    pi*5^2 = 25pi
    25pi/2 = 12.5pi
    12.5pi*3=37.5pi
    50+37.5pi=

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