1. (2a-b) (2a-b) I got 2a^2-b^2. Am I right?
2. 2 (5-8)^2-10/2 I got 4. Am I right?
3. Given g (x)=-x^2+2x-4, find g (-a) I got g (-a)=a^2+2a-4
1.) This uses the FOIL (First, outside, inside, last) system, where each term of one polynomial is multiplied with each term with the other polynomial. So.
(2a-b)*(2a-b) can be broken down to FIRST: (2a*2a) + OUT: (2a*-b) + IN: (-b*2a) + LAST: (-b*-b) which will become 4a^2 + (-2ab) + (-2ab) + (b^2). Add the like terms to give the final answer of 4a^2 - 4ab + b^2
This questions uses PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction in that order)
So with 2*(5-8)^2-10/2 we have parenthesis (5-8) = (-3). There is an exponent (-3)^2 which becomes +9. Now we have 2*9 - (10/2). Using multiplication and division, the equation can be simplified to 18 - 5, which is equal to 13.
3.) Given g (x)=-x^2+2x-4, find g (-a)
This problem is simple as it simply wants you to insert (-a) wherever there is an (x). So it becomes (-(-a))^2 + 2(-a) - 4, which can be simplified to a^2 - 2a -4.
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