I need some math help?

[lanadelrey25]

After this I'll have one more in the update, pleaseeee help lol

https://ibb.co/rpgYjyr

Updates:

1 y

PLEASE don't be scared

[fabi1998]

Your equation : D=E*Y
E is an n×n matrix and you can assume that it had an inverse matrix as stated in your problem.
Let's assume E^-1 is the inverse matrix.
Now multiply that matrix from the write side to the equation and you get:
E^-1*D = E^-1*E*Y
Note that the matrix matrix multiplication is not commutative ! so order matters you have to multiply the matrix from both sides to the left otherwise you don't have an equality anymore.

Now a Matrix multiplied by it's inverse Matrix
(in your example E^-1*E ) always becomes the identity matrix let's call that matrix Id
So you get: E^-1*D = Id*Y

Note that any Matrix multiplied by the identity matrix is by definition the matrix itself.
Therefore: Y = E^-1*D
Where E^-1 is the inverse matrix of E

[Red_Arrow]

The answer to your matrix question depends on which pill you choose.
Lol. The math you are doing is something that leaked out of my brain long ago. I will say, that when I went to high school, that was beyond us. I had to wait till college for that. I give you a lot of credit for being involved with such math in high school!

[menina]

I'm really sorry I can't help you with that. 😕 I suck at math and I've never had to do that kind of exercises.

[NYCQuestions1976]

I'm pretty sure Y = n in your example, because:

E = n × n (or n²). So if D = E × Y, that should be the same as D = n × n × Y, because Y is the same as 1 × n.

Don't hold me to this. It'sbeen a long time since I've done mathematics like this. 👍

[DJB72]

You don't need G@G for this. Questions about the Matrix should be addressed to Neo...

[Jjpayne]

But I frightened 😩 I scared 😟

But seriously my recommendation is Khan academy

It's on YouTube for free last time I checked 🤔

[blondfrog]

Your smarter than you let on huh? If that's the kind of math you are doing then your level of math is more intellectual than mine. I stopped at like linear algebra lol.

[jasco]

go to Cymath on play or app store

[Adogdog]

I might be able to help, send me a message.

[Diversity_Hire]

Nope. No. Nope.

[Waldoe]

Banana?