Did the answers work from josh?
The answers for number 3 and 5 change depending if you use the rounded answers found in previous parts, or exact
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OC= cos (92/2)×8
BC=sin (92/2)×8
Area of triangle= BC×OC÷2
AREA OF OADB= PI× 8^2* 92/360
PERCENTAGE OF SHADE AREA= TRIANGLE AREA/ OADB AREA ×100Looks like it has been answered. Let me know if, any further help is required
Go study and put in the hardwork urself.
You already asked this.
Lol glad it's in the past for me lol
Boii
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