I have no idea how to do number #29!!! It doesn't even look like a linear equation to me. Please tell me where to at least start. Thankx you
Most Helpful Guy
The x intercept is the point (or points) on a curve where y is zero. That's all. The y intercept is the point (or points) where x is zero. For #29, when y is zero you have 0 = 2x^3 - 4x^2 = x^2(x - 4). This curve has two x intercepts. You can probably do the rest now.
This is all pretty pointless in my opinion. Not algebra, which is a useful way to solve problems, but all the stupid vocabulary that mostly real mathematicians don't use, like "x-intercept". I did graduate work in math. Don't think I ever said "x-intercept" after high school.