Help with my physics problem?

[Anonymous]

A small block with mass 0.0525kg slides in a vertical circle of radius 0.0760m on the inside of a circular track. There is no friction between the track and the block. At the bottom of the block's path, the normal force the track exerts on the block has magnitude 3.55N.

What is the magnitude of the normal force that the track exerts on the block when it is at the top of its path?
Express your answer with the appropriate units.
nt=?

[rthomas43]

F=ma
F is going to be the normal force and mg
You change ma to (1/2) m (v^2)

Calculate the velocity of the block at the bottom.
At the bottom, all of the energy is kinetic. At the top, some of it is potential, and some it is kinetic.

KE of the bottom = PE at top + KE at top

Use that formula to find the velocity at the top.
Plug in that velocity into your force equation to find the normal force.

[rthomas43]

((1/2) m (v^2)) / r

My bad, forgot the radius.

[rthomas43]

God dammit.

Replace (.5mv^2)/r with (mv^2) / r

My bad. I gave you some weird fucked up hybrid equation. lol

[Asker]

Cool! Thanks man greatly appreciated.

[rthomas43]

What answer did you get?

[Anonymous]

https://i.imgur.com/7UkcGAn.gif

Appropriate.

[Asker]

Seems appropriate.