Suppose an investment of $1,800 doubles in value every 7 years. How much is the investment worth after 42 years?

[sleepycabin]

A. $21,600

B. $115,200

C. $151,200

D. $25,200

[ZanyInternetName]

1. Do your homework yourself.

2. It is worth g^(t/p)*s dollars. g being the growth rate, t the time since investment, p the period to increase and s the starting value. That means 2^(42/7)*1800=2^(6)*1800=64*1800=115200 is the right answer.

I didn't even need a calculator.

[Tdieseler]

I really think you should do your math homework by yourself.

[sleepycabin]

no you

[Tdieseler]

hahahaha... its been a long time since math boo boo... and im still good.

[Anonymous]

Is there interest? How is it compounded?

[nailu]

year 7 1800*2=3600
year 14 3600*2=7200
21 7200*2=14,400
28 14,400=28,800
35 28,800*2=57,600
42 57,600*2=$115,200
I’d make that deal all day

[naijagurl]

1800(2^42)^(1/7)=
1800(2^6)=
1800(64)=
115,200

[Anonymous]

yuck... math. I swore I'd never even look at this stuff again. lol

[GetzRekt]

C. $115,200

[GetzRekt]

Sorry, I meant B, lol. But yes, $115,200.

[jacquesvol]

Optimist

[AbdKilani]

115,200 $$

[Anonymous]

B. 115,200.

[TShot]

B obviously

[Anonymous]

I think it's B.

[Opinion Owner]

1 yr = 1800
2 yr = 1800 +1800 = 3600
3yr = 3600+3600 = 7200
4yr = 7200 +7200 = 14400
5yr = 14400 + 14400 = 28800
6 yr = 28800 + 28800 = 57600
7 yr = 57600 + 57600 = 115200

There's an equation to this but I don't remember it. I can just do the basic math in my head so I guestimated it was B.

You're supposed to be learning the equation though.

[laughinglad999]

its A

[laughinglad999]

thanks